6t-4/2t=0

Solution for 6t-4/2t=0 equation:

6t-4/2t=0


Domain of the equation: 2t!=0

t!=0/2

t!=0

t∈R


We multiply all the terms by the denominator


6t*2t-4=0

Wy multiply elements

12t^2-4=0

a = 12; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·12·(-4)
Δ = 192
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{192}=\sqrt{64*3}=\sqrt{64}*\sqrt{3}=8\sqrt{3}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{3}}{2*12}=\frac{0-8\sqrt{3}}{24}
=-\frac{8\sqrt{3}}{24}
=-\frac{\sqrt{3}}{3}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{3}}{2*12}=\frac{0+8\sqrt{3}}{24}
=\frac{8\sqrt{3}}{24}
=\frac{\sqrt{3}}{3}
$