6t+1/6t-5=2t+4/2t-7

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Solution for 6t+1/6t-5=2t+4/2t-7 equation: 



6t+1/6t-5=2t+4/2t-7

We move all terms to the left:

6t+1/6t-5-(2t+4/2t-7)=0



Domain of the equation: 6t!=0

t!=0/6

t!=0

t∈R





Domain of the equation: 2t-7)!=0

t∈R



We get rid of parentheses

6t+1/6t-2t-4/2t+7-5=0

We calculate fractions


6t-2t+2t/12t^2+(-24t)/12t^2+7-5=0

We add all the numbers together, and all the variables

4t+2t/12t^2+(-24t)/12t^2+2=0

We multiply all the terms by the denominator


4t*12t^2+2t+(-24t)+2*12t^2=0

We add all the numbers together, and all the variables

2t+4t*12t^2+(-24t)+2*12t^2=0

Wy multiply elements

48t^3+24t^2+2t+(-24t)=0

We get rid of parentheses

48t^3+24t^2+2t-24t=0

We do not support etpression: t^3

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