6r+6(2+5r)=-6(7r-2)+8r

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Solution for 6r+6(2+5r)=-6(7r-2)+8r equation: 



6r+6(2+5r)=-6(7r-2)+8r

We move all terms to the left:

6r+6(2+5r)-(-6(7r-2)+8r)=0

We add all the numbers together, and all the variables

6r+6(5r+2)-(-6(7r-2)+8r)=0

We multiply parentheses

6r+30r-(-6(7r-2)+8r)+12=0



We calculate terms in parentheses: -(-6(7r-2)+8r), so:

-6(7r-2)+8r

We add all the numbers together, and all the variables

8r-6(7r-2)

We multiply parentheses

8r-42r+12

We add all the numbers together, and all the variables

-34r+12

Back to the equation:

-(-34r+12)



We add all the numbers together, and all the variables

36r-(-34r+12)+12=0

We get rid of parentheses

36r+34r-12+12=0

We add all the numbers together, and all the variables

70r=0

r=0/70

r=0

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