6r+6(1-7r)=6(-2r-3)

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Solution for 6r+6(1-7r)=6(-2r-3) equation: 



6r+6(1-7r)=6(-2r-3)

We move all terms to the left:

6r+6(1-7r)-(6(-2r-3))=0

We add all the numbers together, and all the variables

6r+6(-7r+1)-(6(-2r-3))=0

We multiply parentheses

6r-42r-(6(-2r-3))+6=0



We calculate terms in parentheses: -(6(-2r-3)), so:

6(-2r-3)

We multiply parentheses

-12r-18

Back to the equation:

-(-12r-18)



We add all the numbers together, and all the variables

-36r-(-12r-18)+6=0

We get rid of parentheses

-36r+12r+18+6=0

We add all the numbers together, and all the variables

-24r+24=0

We move all terms containing r to the left, all other terms to the right

-24r=-24

r=-24/-24

r=1

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