6r+40=4(1+3r)

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Solution for 6r+40=4(1+3r) equation: 



6r+40=4(1+3r)

We move all terms to the left:

6r+40-(4(1+3r))=0

We add all the numbers together, and all the variables

6r-(4(3r+1))+40=0



We calculate terms in parentheses: -(4(3r+1)), so:

4(3r+1)

We multiply parentheses

12r+4

Back to the equation:

-(12r+4)



We get rid of parentheses

6r-12r-4+40=0

We add all the numbers together, and all the variables

-6r+36=0

We move all terms containing r to the left, all other terms to the right

-6r=-36

r=-36/-6

r=+6

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