6q-(8q+3)=9-(12q-7)

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Solution for 6q-(8q+3)=9-(12q-7) equation: 



6q-(8q+3)=9-(12q-7)

We move all terms to the left:

6q-(8q+3)-(9-(12q-7))=0

We get rid of parentheses

6q-8q-(9-(12q-7))-3=0



We calculate terms in parentheses: -(9-(12q-7)), so:

9-(12q-7)

determiningTheFunctionDomain
-(12q-7)+9

We get rid of parentheses

-12q+7+9

We add all the numbers together, and all the variables

-12q+16

Back to the equation:

-(-12q+16)



We add all the numbers together, and all the variables

-2q-(-12q+16)-3=0

We get rid of parentheses

-2q+12q-16-3=0

We add all the numbers together, and all the variables

10q-19=0

We move all terms containing q to the left, all other terms to the right

10q=19

q=19/10

q=1+9/10

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