6q-(2q+12)=5-(4q-6)

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Solution for 6q-(2q+12)=5-(4q-6) equation: 



6q-(2q+12)=5-(4q-6)

We move all terms to the left:

6q-(2q+12)-(5-(4q-6))=0

We get rid of parentheses

6q-2q-(5-(4q-6))-12=0



We calculate terms in parentheses: -(5-(4q-6)), so:

5-(4q-6)

determiningTheFunctionDomain
-(4q-6)+5

We get rid of parentheses

-4q+6+5

We add all the numbers together, and all the variables

-4q+11

Back to the equation:

-(-4q+11)



We add all the numbers together, and all the variables

4q-(-4q+11)-12=0

We get rid of parentheses

4q+4q-11-12=0

We add all the numbers together, and all the variables

8q-23=0

We move all terms containing q to the left, all other terms to the right

8q=23

q=23/8

q=2+7/8

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