6q+2q+12=4(3+2q)

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Solution for 6q+2q+12=4(3+2q) equation: 



6q+2q+12=4(3+2q)

We move all terms to the left:

6q+2q+12-(4(3+2q))=0

We add all the numbers together, and all the variables

6q+2q-(4(2q+3))+12=0

We add all the numbers together, and all the variables

8q-(4(2q+3))+12=0



We calculate terms in parentheses: -(4(2q+3)), so:

4(2q+3)

We multiply parentheses

8q+12

Back to the equation:

-(8q+12)



We get rid of parentheses

8q-8q-12+12=0

We add all the numbers together, and all the variables

=0

q=0/1

q=0

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