6p2-8p+2=0

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Solution for 6p2-8p+2=0 equation: 



6p^2-8p+2=0

a = 6; b = -8; c = +2;
Δ = b2-4ac
Δ = -82-4·6·2
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$


$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-4}{2*6}=\frac{4}{12}
=1/3
$


$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+4}{2*6}=\frac{12}{12}
=1
$

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