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6p-16/p=3
We move all terms to the left:
6p-16/p-(3)=0
Domain of the equation: p!=0We multiply all the terms by the denominator
p∈R
6p*p-3*p-16=0
We add all the numbers together, and all the variables
-3p+6p*p-16=0
Wy multiply elements
6p^2-3p-16=0
a = 6; b = -3; c = -16;
Δ = b2-4ac
Δ = -32-4·6·(-16)
Δ = 393
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{393}}{2*6}=\frac{3-\sqrt{393}}{12} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{393}}{2*6}=\frac{3+\sqrt{393}}{12} $
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