6p+-(5p+5)=-8+-2(1p+12)

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Solution for 6p+-(5p+5)=-8+-2(1p+12) equation: 



6p+-(5p+5)=-8+-2(1p+12)

We move all terms to the left:

6p+-(5p+5)-(-8+-2(1p+12))=0

We add all the numbers together, and all the variables

6p-(5p+5)-(-8+-2(p+12))+=0

We add all the numbers together, and all the variables

6p-(5p+5)-(-8+-2(p+12))=0

We use the square of the difference formula

6p-(5p+5)-(-8-2(p+12))=0

We get rid of parentheses

6p-5p-(-8-2(p+12))-5=0



We calculate terms in parentheses: -(-8-2(p+12)), so:

-8-2(p+12)

determiningTheFunctionDomain
-2(p+12)-8

We multiply parentheses

-2p-24-8

We add all the numbers together, and all the variables

-2p-32

Back to the equation:

-(-2p-32)



We add all the numbers together, and all the variables

p-(-2p-32)-5=0

We get rid of parentheses

p+2p+32-5=0

We add all the numbers together, and all the variables

3p+27=0

We move all terms containing p to the left, all other terms to the right

3p=-27

p=-27/3

p=-9

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