6n-38=4(1+3n)+8n

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Solution for 6n-38=4(1+3n)+8n equation: 



6n-38=4(1+3n)+8n

We move all terms to the left:

6n-38-(4(1+3n)+8n)=0

We add all the numbers together, and all the variables

6n-(4(3n+1)+8n)-38=0



We calculate terms in parentheses: -(4(3n+1)+8n), so:

4(3n+1)+8n

We add all the numbers together, and all the variables

8n+4(3n+1)

We multiply parentheses

8n+12n+4

We add all the numbers together, and all the variables

20n+4

Back to the equation:

-(20n+4)



We get rid of parentheses

6n-20n-4-38=0

We add all the numbers together, and all the variables

-14n-42=0

We move all terms containing n to the left, all other terms to the right

-14n=42

n=42/-14

n=-3

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