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6n(2n+5)=66
We move all terms to the left:
6n(2n+5)-(66)=0
We multiply parentheses
12n^2+30n-66=0
a = 12; b = 30; c = -66;
Δ = b2-4ac
Δ = 302-4·12·(-66)
Δ = 4068
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4068}=\sqrt{36*113}=\sqrt{36}*\sqrt{113}=6\sqrt{113}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-6\sqrt{113}}{2*12}=\frac{-30-6\sqrt{113}}{24} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+6\sqrt{113}}{2*12}=\frac{-30+6\sqrt{113}}{24} $
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