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6m-3/2m=-3
We move all terms to the left:
6m-3/2m-(-3)=0
Domain of the equation: 2m!=0We add all the numbers together, and all the variables
m!=0/2
m!=0
m∈R
6m-3/2m+3=0
We multiply all the terms by the denominator
6m*2m+3*2m-3=0
Wy multiply elements
12m^2+6m-3=0
a = 12; b = 6; c = -3;
Δ = b2-4ac
Δ = 62-4·12·(-3)
Δ = 180
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{180}=\sqrt{36*5}=\sqrt{36}*\sqrt{5}=6\sqrt{5}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6\sqrt{5}}{2*12}=\frac{-6-6\sqrt{5}}{24} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6\sqrt{5}}{2*12}=\frac{-6+6\sqrt{5}}{24} $
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