6k-3(5k+2)=4(1-k)

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Solution for 6k-3(5k+2)=4(1-k) equation: 



6k-3(5k+2)=4(1-k)

We move all terms to the left:

6k-3(5k+2)-(4(1-k))=0

We add all the numbers together, and all the variables

6k-3(5k+2)-(4(-1k+1))=0

We multiply parentheses

6k-15k-(4(-1k+1))-6=0



We calculate terms in parentheses: -(4(-1k+1)), so:

4(-1k+1)

We multiply parentheses

-4k+4

Back to the equation:

-(-4k+4)



We add all the numbers together, and all the variables

-9k-(-4k+4)-6=0

We get rid of parentheses

-9k+4k-4-6=0

We add all the numbers together, and all the variables

-5k-10=0

We move all terms containing k to the left, all other terms to the right

-5k=10

k=10/-5

k=-2

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