6k(1+2k)-6k=-3(8k+4)

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Solution for 6k(1+2k)-6k=-3(8k+4) equation: 



6k(1+2k)-6k=-3(8k+4)

We move all terms to the left:

6k(1+2k)-6k-(-3(8k+4))=0

We add all the numbers together, and all the variables

6k(2k+1)-6k-(-3(8k+4))=0

We add all the numbers together, and all the variables

-6k+6k(2k+1)-(-3(8k+4))=0

We multiply parentheses

12k^2-6k+6k-(-3(8k+4))=0



We calculate terms in parentheses: -(-3(8k+4)), so:

-3(8k+4)

We multiply parentheses

-24k-12

Back to the equation:

-(-24k-12)



We add all the numbers together, and all the variables

12k^2-(-24k-12)=0

We get rid of parentheses

12k^2+24k+12=0

a = 12; b = 24; c = +12;
Δ = b2-4ac
Δ = 242-4·12·12
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$k=\frac{-b}{2a}=\frac{-24}{24}=-1$

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