6i(3-2i)=0

Solution for 6i(3-2i)=0 equation:

6i(3-2i)=0

We add all the numbers together, and all the variables

6i(-2i+3)=0

We multiply parentheses

-12i^2+18i=0

a = -12; b = 18; c = 0;
Δ = b2-4ac
Δ = 182-4·(-12)·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-18}{2*-12}=\frac{-36}{-24}
=1+1/2
$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+18}{2*-12}=\frac{0}{-24}
=0
$