6h(h+4)=-2h

Solution for 6h(h+4)=-2h equation:

6h(h+4)=-2h

We move all terms to the left:

6h(h+4)-(-2h)=0

We multiply parentheses

6h^2+24h-(-2h)=0

We get rid of parentheses

6h^2+24h+2h=0

We add all the numbers together, and all the variables

6h^2+26h=0

a = 6; b = 26; c = 0;
Δ = b2-4ac
Δ = 262-4·6·0
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-26}{2*6}=\frac{-52}{12}
=-4+1/3
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+26}{2*6}=\frac{0}{12}
=0
$