6h(3-1)=18h-6h=12h

Solution for 6h(3-1)=18h-6h=12h equation:

6h(3-1)=18h-6h=12h

We move all terms to the left:

6h(3-1)-(18h-6h)=0

We add all the numbers together, and all the variables

6h2-(+12h)=0

We add all the numbers together, and all the variables

6h^2-(+12h)=0

We get rid of parentheses

6h^2-12h=0

a = 6; b = -12; c = 0;
Δ = b2-4ac
Δ = -122-4·6·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-12}{2*6}=\frac{0}{12}
=0
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+12}{2*6}=\frac{24}{12}
=2
$