6g+29(-7+2g)=1-g

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Solution for 6g+29(-7+2g)=1-g equation: 



6g+29(-7+2g)=1-g

We move all terms to the left:

6g+29(-7+2g)-(1-g)=0

We add all the numbers together, and all the variables

6g+29(2g-7)-(-1g+1)=0

We multiply parentheses

6g+58g-(-1g+1)-203=0

We get rid of parentheses

6g+58g+1g-1-203=0

We add all the numbers together, and all the variables

65g-204=0

We move all terms containing g to the left, all other terms to the right

65g=204

g=204/65

g=3+9/65

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