6g(-2g-1)=-(13g+2)

Solution for 6g(-2g-1)=-(13g+2) equation:

6g(-2g-1)=-(13g+2)

We move all terms to the left:

6g(-2g-1)-(-(13g+2))=0

We multiply parentheses

-12g^2-6g-(-(13g+2))=0


We calculate terms in parentheses: -(-(13g+2)), so:

-(13g+2)

We get rid of parentheses

-13g-2

Back to the equation:

-(-13g-2)


We get rid of parentheses

-12g^2-6g+13g+2=0

We add all the numbers together, and all the variables

-12g^2+7g+2=0

a = -12; b = 7; c = +2;
Δ = b2-4ac
Δ = 72-4·(-12)·2
Δ = 145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{145}}{2*-12}=\frac{-7-\sqrt{145}}{-24}
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{145}}{2*-12}=\frac{-7+\sqrt{145}}{-24}
$