6f+5=2(2+3f)+1

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Solution for 6f+5=2(2+3f)+1 equation: 



6f+5=2(2+3f)+1

We move all terms to the left:

6f+5-(2(2+3f)+1)=0

We add all the numbers together, and all the variables

6f-(2(3f+2)+1)+5=0



We calculate terms in parentheses: -(2(3f+2)+1), so:

2(3f+2)+1

We multiply parentheses

6f+4+1

We add all the numbers together, and all the variables

6f+5

Back to the equation:

-(6f+5)



We get rid of parentheses

6f-6f-5+5=0

We add all the numbers together, and all the variables

=0

f=0/1

f=0

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