6cos(2x)+7cos(x)+7=0

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Solution for 6cos(2x)+7cos(x)+7=0 equation:


Simplifying
6cos(2x) + 7cos(x) + 7 = 0

Remove parenthesis around (2x)
6cos * 2x + 7cos(x) + 7 = 0

Reorder the terms for easier multiplication:
6 * 2cos * x + 7cos(x) + 7 = 0

Multiply 6 * 2
12cos * x + 7cos(x) + 7 = 0

Multiply cos * x
12cosx + 7cos(x) + 7 = 0

Multiply cos * x
12cosx + 7cosx + 7 = 0

Reorder the terms:
7 + 12cosx + 7cosx = 0

Combine like terms: 12cosx + 7cosx = 19cosx
7 + 19cosx = 0

Solving
7 + 19cosx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-7' to each side of the equation.
7 + -7 + 19cosx = 0 + -7

Combine like terms: 7 + -7 = 0
0 + 19cosx = 0 + -7
19cosx = 0 + -7

Combine like terms: 0 + -7 = -7
19cosx = -7

Divide each side by '19osx'.
c = -0.3684210526o-1s-1x-1

Simplifying
c = -0.3684210526o-1s-1x-1

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