6c+2=2(3c+1)

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Solution for 6c+2=2(3c+1) equation: 



6c+2=2(3c+1)

We move all terms to the left:

6c+2-(2(3c+1))=0



We calculate terms in parentheses: -(2(3c+1)), so:

2(3c+1)

We multiply parentheses

6c+2

Back to the equation:

-(6c+2)



We get rid of parentheses

6c-6c-2+2=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0

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