6b-5=-3(b-2)

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Solution for 6b-5=-3(b-2) equation: 



6b-5=-3(b-2)

We move all terms to the left:

6b-5-(-3(b-2))=0



We calculate terms in parentheses: -(-3(b-2)), so:

-3(b-2)

We multiply parentheses

-3b+6

Back to the equation:

-(-3b+6)



We get rid of parentheses

6b+3b-6-5=0

We add all the numbers together, and all the variables

9b-11=0

We move all terms containing b to the left, all other terms to the right

9b=11

b=11/9

b=1+2/9

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