6b-5=(b+2)

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Solution for 6b-5=(b+2) equation: 



6b-5=(b+2)

We move all terms to the left:

6b-5-((b+2))=0



We calculate terms in parentheses: -((b+2)), so:

(b+2)

We get rid of parentheses

b+2

Back to the equation:

-(b+2)



We get rid of parentheses

6b-b-2-5=0

We add all the numbers together, and all the variables

5b-7=0

We move all terms containing b to the left, all other terms to the right

5b=7

b=7/5

b=1+2/5

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