6b-4=8(2+1/4b)

Solution for 6b-4=8(2+1/4b) equation:

6b-4=8(2+1/4b)

We move all terms to the left:

6b-4-(8(2+1/4b))=0


Domain of the equation: 4b))!=0

b!=0/1

b!=0

b∈R


We add all the numbers together, and all the variables

6b-(8(1/4b+2))-4=0

We multiply all the terms by the denominator


6b*4b-4*4b+2))-(8(1+2))=0

We add all the numbers together, and all the variables

6b*4b-4*4b+2))-(83)=0

We add all the numbers together, and all the variables

6b*4b-4*4b=0

Wy multiply elements

24b^2-16b=0

a = 24; b = -16; c = 0;
Δ = b2-4ac
Δ = -162-4·24·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-16}{2*24}=\frac{0}{48}
=0
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+16}{2*24}=\frac{32}{48}
=2/3
$