6b+2b=5(b+1)-5(1+3b)

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Solution for 6b+2b=5(b+1)-5(1+3b) equation:


Simplifying
6b + 2b = 5(b + 1) + -5(1 + 3b)

Combine like terms: 6b + 2b = 8b
8b = 5(b + 1) + -5(1 + 3b)

Reorder the terms:
8b = 5(1 + b) + -5(1 + 3b)
8b = (1 * 5 + b * 5) + -5(1 + 3b)
8b = (5 + 5b) + -5(1 + 3b)
8b = 5 + 5b + (1 * -5 + 3b * -5)
8b = 5 + 5b + (-5 + -15b)

Reorder the terms:
8b = 5 + -5 + 5b + -15b

Combine like terms: 5 + -5 = 0
8b = 0 + 5b + -15b
8b = 5b + -15b

Combine like terms: 5b + -15b = -10b
8b = -10b

Solving
8b = -10b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '10b' to each side of the equation.
8b + 10b = -10b + 10b

Combine like terms: 8b + 10b = 18b
18b = -10b + 10b

Combine like terms: -10b + 10b = 0
18b = 0

Divide each side by '18'.
b = 0

Simplifying
b = 0

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