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6a-1/2a=2
We move all terms to the left:
6a-1/2a-(2)=0
Domain of the equation: 2a!=0We multiply all the terms by the denominator
a!=0/2
a!=0
a∈R
6a*2a-2*2a-1=0
Wy multiply elements
12a^2-4a-1=0
a = 12; b = -4; c = -1;
Δ = b2-4ac
Δ = -42-4·12·(-1)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-8}{2*12}=\frac{-4}{24} =-1/6 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+8}{2*12}=\frac{12}{24} =1/2 $
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