6a-(10-a)=20-(a+2)

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Solution for 6a-(10-a)=20-(a+2) equation: 



6a-(10-a)=20-(a+2)

We move all terms to the left:

6a-(10-a)-(20-(a+2))=0

We add all the numbers together, and all the variables

6a-(-1a+10)-(20-(a+2))=0

We get rid of parentheses

6a+1a-(20-(a+2))-10=0



We calculate terms in parentheses: -(20-(a+2)), so:

20-(a+2)

determiningTheFunctionDomain
-(a+2)+20

We get rid of parentheses

-a-2+20

We add all the numbers together, and all the variables

-1a+18

Back to the equation:

-(-1a+18)



We add all the numbers together, and all the variables

7a-(-1a+18)-10=0

We get rid of parentheses

7a+1a-18-10=0

We add all the numbers together, and all the variables

8a-28=0

We move all terms containing a to the left, all other terms to the right

8a=28

a=28/8

a=3+1/2

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