6=8/y2+4

Solution for 6=8/y2+4 equation:

6=8/y2+4

We move all terms to the left:

6-(8/y2+4)=0


Domain of the equation: y2+4)!=0

y∈R


We get rid of parentheses

-8/y2-4+6=0

We multiply all the terms by the denominator


-4*y2+6*y2-8=0

We add all the numbers together, and all the variables

2y^2-8=0

a = 2; b = 0; c = -8;
Δ = b2-4ac
Δ = 02-4·2·(-8)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8}{2*2}=\frac{-8}{4}
=-2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8}{2*2}=\frac{8}{4}
=2
$