6=5(3a-5)-4(a-5)

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Solution for 6=5(3a-5)-4(a-5) equation: 



6=5(3a-5)-4(a-5)

We move all terms to the left:

6-(5(3a-5)-4(a-5))=0



We calculate terms in parentheses: -(5(3a-5)-4(a-5)), so:

5(3a-5)-4(a-5)

We multiply parentheses

15a-4a-25+20

We add all the numbers together, and all the variables

11a-5

Back to the equation:

-(11a-5)



We get rid of parentheses

-11a+5+6=0

We add all the numbers together, and all the variables

-11a+11=0

We move all terms containing a to the left, all other terms to the right

-11a=-11

a=-11/-11

a=1

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