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6=3+5(5-d)
We move all terms to the left:
6-(3+5(5-d))=0
We add all the numbers together, and all the variables
-(3+5(-1d+5))+6=0
We calculate terms in parentheses: -(3+5(-1d+5)), so:We get rid of parentheses
3+5(-1d+5)
determiningTheFunctionDomain 5(-1d+5)+3
We multiply parentheses
-5d+25+3
We add all the numbers together, and all the variables
-5d+28
Back to the equation:
-(-5d+28)
5d-28+6=0
We add all the numbers together, and all the variables
5d-22=0
We move all terms containing d to the left, all other terms to the right
5d=22
d=22/5
d=4+2/5
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