6=3(k-4)

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Solution for 6=3(k-4) equation: 



6=3(k-4)

We move all terms to the left:

6-(3(k-4))=0



We calculate terms in parentheses: -(3(k-4)), so:

3(k-4)

We multiply parentheses

3k-12

Back to the equation:

-(3k-12)



We get rid of parentheses

-3k+12+6=0

We add all the numbers together, and all the variables

-3k+18=0

We move all terms containing k to the left, all other terms to the right

-3k=-18

k=-18/-3

k=+6

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