6=2c-(12-2c)+12

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Solution for 6=2c-(12-2c)+12 equation: 



6=2c-(12-2c)+12

We move all terms to the left:

6-(2c-(12-2c)+12)=0

We add all the numbers together, and all the variables

-(2c-(-2c+12)+12)+6=0



We calculate terms in parentheses: -(2c-(-2c+12)+12), so:

2c-(-2c+12)+12

We get rid of parentheses

2c+2c-12+12

We add all the numbers together, and all the variables

4c

Back to the equation:

-(4c)



We move all terms containing c to the left, all other terms to the right

-4c=-6

c=-6/-4

c=1+1/2

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