6=2(z+1)

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Solution for 6=2(z+1) equation: 



6=2(z+1)

We move all terms to the left:

6-(2(z+1))=0



We calculate terms in parentheses: -(2(z+1)), so:

2(z+1)

We multiply parentheses

2z+2

Back to the equation:

-(2z+2)



We get rid of parentheses

-2z-2+6=0

We add all the numbers together, and all the variables

-2z+4=0

We move all terms containing z to the left, all other terms to the right

-2z=-4

z=-4/-2

z=+2

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