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6=2(y+8)7y
We move all terms to the left:
6-(2(y+8)7y)=0
We calculate terms in parentheses: -(2(y+8)7y), so:We get rid of parentheses
2(y+8)7y
We multiply parentheses
14y^2+112y
Back to the equation:
-(14y^2+112y)
-14y^2-112y+6=0
a = -14; b = -112; c = +6;
Δ = b2-4ac
Δ = -1122-4·(-14)·6
Δ = 12880
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12880}=\sqrt{16*805}=\sqrt{16}*\sqrt{805}=4\sqrt{805}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-112)-4\sqrt{805}}{2*-14}=\frac{112-4\sqrt{805}}{-28} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-112)+4\sqrt{805}}{2*-14}=\frac{112+4\sqrt{805}}{-28} $
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