6=2(b+1)

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Solution for 6=2(b+1) equation: 



6=2(b+1)

We move all terms to the left:

6-(2(b+1))=0



We calculate terms in parentheses: -(2(b+1)), so:

2(b+1)

We multiply parentheses

2b+2

Back to the equation:

-(2b+2)



We get rid of parentheses

-2b-2+6=0

We add all the numbers together, and all the variables

-2b+4=0

We move all terms containing b to the left, all other terms to the right

-2b=-4

b=-4/-2

b=+2

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