6=2(13+2f)

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Solution for 6=2(13+2f) equation:



6=2(13+2f)
We move all terms to the left:
6-(2(13+2f))=0
We add all the numbers together, and all the variables
-(2(2f+13))+6=0
We calculate terms in parentheses: -(2(2f+13)), so:
2(2f+13)
We multiply parentheses
4f+26
Back to the equation:
-(4f+26)
We get rid of parentheses
-4f-26+6=0
We add all the numbers together, and all the variables
-4f-20=0
We move all terms containing f to the left, all other terms to the right
-4f=20
f=20/-4
f=-5

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