6=0.3(1+x)/(0.1-x)

Solution for 6=0.3(1+x)/(0.1-x) equation:

6=0.3(1+x)/(0.1-x)

We move all terms to the left:

6-(0.3(1+x)/(0.1-x))=0


Domain of the equation: (0.1-x))!=0

We move all terms containing x to the left, all other terms to the right

-x)!=-0.1

x!=-0.1/1

x!=-0.1

x∈R


We add all the numbers together, and all the variables

-(0.3(x+1)/(-1x+0.1))+6=0

We multiply all the terms by the denominator


-(0.3(x+1)+6*(-1x+0.1))=0


We calculate terms in parentheses: -(0.3(x+1)+6*(-1x+0.1)), so:

0.3(x+1)+6*(-1x+0.1)

We multiply parentheses

0.3x-6x+0.3+0.6

We add all the numbers together, and all the variables

-5.7x+0.9

Back to the equation:

-(-5.7x+0.9)


We get rid of parentheses

5.7x-0.9=0

We move all terms containing x to the left, all other terms to the right

5.7x=0.9

x=0.9/5.7

x=0.9/5.7