6=0.01x^2+1.18x+2

Solution for 6=0.01x^2+1.18x+2 equation:

6=0.01x^2+1.18x+2

We move all terms to the left:

6-(0.01x^2+1.18x+2)=0

We get rid of parentheses

-0.01x^2-1.18x-2+6=0

We add all the numbers together, and all the variables

-0.01x^2-1.18x+4=0

a = -0.01; b = -1.18; c = +4;
Δ = b2-4ac
Δ = -1.182-4·(-0.01)·4
Δ = 1.5524
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.18)-\sqrt{1.5524}}{2*-0.01}=\frac{1.18-\sqrt{1.5524}}{-0.02}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.18)+\sqrt{1.5524}}{2*-0.01}=\frac{1.18+\sqrt{1.5524}}{-0.02}
$