6=-4/3(-9)+b

Solution for 6=-4/3(-9)+b equation:

6=-4/3(-9)+b

We move all terms to the left:

6-(-4/3(-9)+b)=0


Domain of the equation: 3(-9)+b)!=0

b∈R


We multiply all the terms by the denominator


-(-4+6*3(-9)+b)=0


We calculate terms in parentheses: -(-4+6*3(-9)+b), so:

-4+6*3(-9)+b

determiningTheFunctionDomain
b-4+6*3(-9)

We add all the numbers together, and all the variables

b-166

Back to the equation:

-(b-166)


We get rid of parentheses

-b+166=0

We add all the numbers together, and all the variables

-1b+166=0

We move all terms containing b to the left, all other terms to the right

-b=-166

b=-166/-1

b=+166