6=-3y+(y-2)

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Solution for 6=-3y+(y-2) equation: 



6=-3y+(y-2)

We move all terms to the left:

6-(-3y+(y-2))=0



We calculate terms in parentheses: -(-3y+(y-2)), so:

-3y+(y-2)

We get rid of parentheses

-3y+y-2

We add all the numbers together, and all the variables

-2y-2

Back to the equation:

-(-2y-2)



We get rid of parentheses

2y+2+6=0

We add all the numbers together, and all the variables

2y+8=0

We move all terms containing y to the left, all other terms to the right

2y=-8

y=-8/2

y=-4

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