6=-2c-(12-2c)+12

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Solution for 6=-2c-(12-2c)+12 equation: 



6=-2c-(12-2c)+12

We move all terms to the left:

6-(-2c-(12-2c)+12)=0

We add all the numbers together, and all the variables

-(-2c-(-2c+12)+12)+6=0



We calculate terms in parentheses: -(-2c-(-2c+12)+12), so:

-2c-(-2c+12)+12

We get rid of parentheses

-2c+2c-12+12

We add all the numbers together, and all the variables



Back to the equation:

-()



We add all the numbers together, and all the variables

=0

c=0/1

c=0

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