6=-1/3x+1x

Solution for 6=-1/3x+1x equation:

6=-1/3x+1x

We move all terms to the left:

6-(-1/3x+1x)=0


Domain of the equation: 3x+1x)!=0

x∈R


We add all the numbers together, and all the variables

-(+x-1/3x)+6=0

We get rid of parentheses

-x+1/3x+6=0

We multiply all the terms by the denominator


-x*3x+6*3x+1=0

Wy multiply elements

-3x^2+18x+1=0

a = -3; b = 18; c = +1;
Δ = b2-4ac
Δ = 182-4·(-3)·1
Δ = 336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{336}=\sqrt{16*21}=\sqrt{16}*\sqrt{21}=4\sqrt{21}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-4\sqrt{21}}{2*-3}=\frac{-18-4\sqrt{21}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+4\sqrt{21}}{2*-3}=\frac{-18+4\sqrt{21}}{-6}
$