6=(z/3)-2

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Solution for 6=(z/3)-2 equation: 



6=(z/3)-2

We move all terms to the left:

6-((z/3)-2)=0

We add all the numbers together, and all the variables

-((+z/3)-2)+6=0

We multiply all the terms by the denominator


-((+z+6*3)-2)=0



We calculate terms in parentheses: -((+z+6*3)-2), so:

(+z+6*3)-2

We add all the numbers together, and all the variables

(z+18)-2

We get rid of parentheses

z+18-2

We add all the numbers together, and all the variables

z+16

Back to the equation:

-(z+16)



We get rid of parentheses

-z-16=0

We add all the numbers together, and all the variables

-1z-16=0

We move all terms containing z to the left, all other terms to the right

-z=16

z=16/-1

z=-16

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