6=(3y-1/2)

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Solution for 6=(3y-1/2) equation: 



6=(3y-1/2)

We move all terms to the left:

6-((3y-1/2))=0

We add all the numbers together, and all the variables

-((+3y-1/2))+6=0

We multiply all the terms by the denominator


-((+3y-1+6*2))=0



We calculate terms in parentheses: -((+3y-1+6*2)), so:

(+3y-1+6*2)

We add all the numbers together, and all the variables

(3y+11)

We get rid of parentheses

3y+11

Back to the equation:

-(3y+11)



We get rid of parentheses

-3y-11=0

We move all terms containing y to the left, all other terms to the right

-3y=11

y=11/-3

y=-3+2/3

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