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6992=x(260-2x)
We move all terms to the left:
6992-(x(260-2x))=0
We add all the numbers together, and all the variables
-(x(-2x+260))+6992=0
We calculate terms in parentheses: -(x(-2x+260)), so:We get rid of parentheses
x(-2x+260)
We multiply parentheses
-2x^2+260x
Back to the equation:
-(-2x^2+260x)
2x^2-260x+6992=0
a = 2; b = -260; c = +6992;
Δ = b2-4ac
Δ = -2602-4·2·6992
Δ = 11664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{11664}=108$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-260)-108}{2*2}=\frac{152}{4} =38 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-260)+108}{2*2}=\frac{368}{4} =92 $
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