68=4m+4(1+3m)

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Solution for 68=4m+4(1+3m) equation: 



68=4m+4(1+3m)

We move all terms to the left:

68-(4m+4(1+3m))=0

We add all the numbers together, and all the variables

-(4m+4(3m+1))+68=0



We calculate terms in parentheses: -(4m+4(3m+1)), so:

4m+4(3m+1)

We multiply parentheses

4m+12m+4

We add all the numbers together, and all the variables

16m+4

Back to the equation:

-(16m+4)



We get rid of parentheses

-16m-4+68=0

We add all the numbers together, and all the variables

-16m+64=0

We move all terms containing m to the left, all other terms to the right

-16m=-64

m=-64/-16

m=+4

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