68=4(2c+5)

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Solution for 68=4(2c+5) equation: 



68=4(2c+5)

We move all terms to the left:

68-(4(2c+5))=0



We calculate terms in parentheses: -(4(2c+5)), so:

4(2c+5)

We multiply parentheses

8c+20

Back to the equation:

-(8c+20)



We get rid of parentheses

-8c-20+68=0

We add all the numbers together, and all the variables

-8c+48=0

We move all terms containing c to the left, all other terms to the right

-8c=-48

c=-48/-8

c=+6

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